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Rank Sitters by City
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Rank Sitters by City

MediumSQL · PostgreSQL

Problem

Write a query using window functions to rank sitters in each city based on their average rating and total completed bookings.

Use the sitters and bookings tables. Include sitters with at least one completed booking, even when their completed bookings have no rating.

Output

  1. One row per eligible sitter with city, sitter_id, sitter_name, average_rating, completed_bookings, and city_rank.
  2. Rank within each city by average rating descending, then completed bookings descending. Place unrated sitters after rated sitters.
  3. Order by city, city_rank, and sitter_id.

Schema

sitters
ColumnTypeDescription
sitter_idPKINTUnique identifier for the sitter
sitter_nameVARCHAR(100)Sitter display name
cityVARCHAR(100)City where the sitter provides services
bookings
ColumnTypeDescription
booking_idPKINTUnique booking identifier
sitter_idINTSitter assigned to the booking
statusVARCHAR(30)Booking status
ratingDECIMAL(3,2)Customer rating for the booking
Tablessittersbookings
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Your question is Rank Sitters by City. Start with the requirements and the two tables in the Question tab.

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