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SQL Productivity by Shift
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SQL Productivity by Shift

MediumSQL · PostgreSQL

Problem

Write a SQL query to calculate labor hours, package volume, and productivity by shift using multiple tables.

Use the provided UPS shift, labor, and package-volume data. Include every shift, treat missing labor or package values as zero, and return productivity as package volume divided by labor hours. Return NULL productivity when labor hours are zero.

Output

  1. One row per shift with shift_date, shift_name, labor_hours, package_volume, and productivity
  2. Order by shift_date, shift_name, and shift_id

Schema

shifts
ColumnTypeDescription
shift_idPKINTUnique shift identifier
shift_dateDATEOperating date of the shift
shift_nameVARCHAR(30)Shift label such as Day or Night
labor_hours
ColumnTypeDescription
labor_idPKINTUnique labor record identifier
shift_idINTReferenced shift
employee_idINTEmployee assigned to the shift
hours_workedNUMERIC(6,2)Hours worked by the employee
package_volume
ColumnTypeDescription
volume_idPKINTUnique package-volume record identifier
shift_idINTReferenced shift
package_countINTPackages processed in the record
Tablesshiftslabor_hourspackage_volume
Interviewer

Your question is SQL Productivity by Shift. Start with the requirements and the three tables in the Question tab.

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