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Given a Number N Sum 1 to N-1
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Given a Number N Sum 1 to N-1

MediumPython

Problem

During QA validation of large totals in the Coupa Supplier Portal, you need to compute the sum of every integer from 1 through N - 1. Because N may contain hundreds of thousands of digits, you must not iterate through the range or convert the entire value to a native integer.

Return the result modulo mod.

Formal Specification

Implement sum_before_mod(n, mod), where:

  • n is a decimal string representing an integer N >= 1.
  • mod is a positive integer.
  • The output is an integer equal to (1 + 2 + ... + (N - 1)) % mod.

Use the identity N * (N - 1) / 2, but divide one factor by 2 before applying the modulo so the method works even when mod is even.

Constraints

  • 1 <= len(n) <= 100000
  • n represents an integer N >= 1
  • 1 <= mod <= 10^18
  • n contains only decimal digits
  • The algorithm must not enumerate the range from 1 through N - 1
  • The algorithm must not use floating-point arithmetic

Function Signature

def sum_before_mod(n, mod):
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