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Find Middle of Linked List
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Find Middle of Linked List

EasyPython

Problem

How would you find the middle node of a linked list?

Implement the solution using a singly linked list and return the middle node's value. If the list has an even number of nodes, return the second middle node. For grading, each node is represented as { "value": number, "next": node_or_null }, and the function receives the head node.

Constraints

  • 1 <= number of nodes <= 1000
  • Each node value is an integer
  • The list is singly linked and acyclic
  • For an even-length list, return the second middle node

Function Signature

def middle_node(head):
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