Foursquare may compare alternate text representations of a place name during Places search processing. Given two strings, determine whether one is a permutation of the other.
Two strings are permutations if they contain exactly the same characters with the same frequencies. Character casing and whitespace are significant, so "Cafe" and "cafe" are different, as are "New York" and "NewYork".
Implement are_permutations(s, t).
s and t.True if t is a permutation of s; otherwise, return False.def are_permutations(s, t):