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Reverse a Linked List

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Your question is Reverse a Linked List. Start with the requirements on the right.

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Problem

Given the head of a singly linked list, reverse the list and return the new head.

Implement the reversal in-place. You may assume the list nodes are represented by a ListNode object with fields val and next.

Formal Specification

  • Input: head, the head node of a singly linked list, or None for an empty list.
  • Output: The head node of the reversed list.

Constraints

  • 0 <= number of nodes <= 10^5
  • -10^9 <= Node.val <= 10^9
  • The list is singly linked
  • Use O(1) extra space if possible

Function Signature

def reverse_linked_list(head):
Your solutionPython 3
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