Dataford
Interview QuestionsInterview GuidesExperiencesMock InterviewsPricing
Get started

Handle a Microcontroller Interrupt

EasyPython00:00
Practice interviewer
In session
5 left
00:00

Your question is Handle a Microcontroller Interrupt. Start with the requirements on the right.

Run and submit as often as you like. When you're ready, talk me through your approach or go straight to the code.

You need to log in / sign up to run or submit.

Problem

In an Actalent embedded firmware prototype, a microcontroller interrupt status register can report several pending sources at once. Implement an interrupt handler that decodes the status bits and appends one event for each recognized source to a bounded FIFO queue.

Formal Specification

Implement handle_interrupt(status, timestamp, queue, capacity, dropped). status and timestamp are integers. queue is a list of event dictionaries in chronological order, and capacity is its maximum length. dropped is the number of events previously rejected because the queue was full.

Use these status bits:

  • 1: timer interrupt, event type "TIMER"
  • 2: receive interrupt, event type "RX"
  • 4: error interrupt, event type "ERROR"

For every recognized bit, create {"type": event_type, "timestamp": timestamp}. Process events in priority order: ERROR, RX, then TIMER. If the queue is full, do not remove existing events and increment dropped for each rejected event. Ignore unknown bits. Return (queue, dropped).

Constraints

  • 0 <= status < 16
  • 0 <= timestamp <= 2^31 - 1
  • 0 <= len(queue) <= capacity <= 10^5
  • dropped >= 0
  • Input queue events are valid and already ordered from oldest to newest

Function Signature

def handle_interrupt(status, timestamp, queue, capacity, dropped):
Your solutionPython 3
You need to log in / sign up to run or submit.
Run your code to see test output