Explain the Fizz Buzz Process

Describe the process you would use to solve the Fizz Buzz problem. Walk through the logic, the order of checks, and the time complexity.

Iteration with a loop

Fizz Buzz is solved by visiting each integer in order, usually from 1 through n. A loop is the natural control structure because the same decision logic must be applied to every number.

for i in range(1, n + 1):
    pass

Modulo for divisibility

The modulo operator checks whether a number is divisible by another number. If i % 3 == 0, the number is divisible by 3; if i % 5 == 0, it is divisible by 5.

if i % 3 == 0:
    print("Fizz")

Order of conditional checks

The combined case must be checked before the individual cases. If you check divisibility by 3 first, then 15 would incorrectly produce Fizz instead of FizzBuzz.

if i % 3 == 0 and i % 5 == 0:
    value = "FizzBuzz"
elif i % 3 == 0:
    value = "Fizz"
elif i % 5 == 0:
    value = "Buzz"

Output construction

For each number, you either emit a string replacement or the number itself. This can be printed directly or stored in a list if the function needs to return results.

else:
    value = str(i)