Even or Odd Check

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Your question is Even or Odd Check. Start with the requirements on the right.

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Problem

The GEICO Mobile claims experience receives numeric claim identifiers and needs a small utility to classify each identifier as "even" or "odd". Given one integer, determine its parity programmatically.

Formal Specification

Implement classify_parity(number).

Input: number, an integer.
Output: Return the string "even" if the integer is divisible by 2; otherwise, return "odd".
Zero is considered even. Negative integers must be handled correctly.

Constraints

-10^18 <= number <= 10^18
number is an integer
Return exactly "even" or "odd"

Function Signature

def classify_parity(number):

Your solutionPython 3

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