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Count Less Than Using Binary Search
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Count Less Than Using Binary Search

EasyPython

Problem

The Expedia app stores available hotel prices in a sorted integer array. Given the sorted prices and a target price, return how many prices are strictly less than the target.

You must solve the problem using binary search. Duplicate prices should be counted separately, and a price equal to the target is not considered less.

Formal Specification

Implement count_less_than(prices, target).

  • Input: prices, a nondecreasing list of integers, and target, an integer.
  • Output: An integer representing the number of elements in prices whose value is strictly less than target.
  • The input list must not be modified.

Constraints

  • 0 <= len(prices) <= 100,000
  • -10^9 <= prices[i], target <= 10^9
  • prices is sorted in nondecreasing order
  • Duplicate values are allowed

Function Signature

def count_less_than(prices, target):
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